1/7x^2=5/7x

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Solution for 1/7x^2=5/7x equation: 


x in (-oo:+oo)

(1/7)*x^2 = (5/7)*x // - (5/7)*x

(1/7)*x^2-((5/7)*x) = 0

(1/7)*x^2+(-5/7)*x = 0

1/7*x^2-5/7*x = 0

DELTA = (-5/7)^2-(0*1/7*4)

DELTA = 25/49

DELTA > 0

x = ((25/49)^(1/2)+5/7)/(1/7*2) or x = (5/7-(25/49)^(1/2))/(1/7*2)

x = 5 or x = 0

x in { 0, 5 }

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